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If each edge of cube is 1 by so%find en in surface area |
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Answer» Initial Surface Area,A1=6x2A1=6x2 The edge increased by 50%, so, the final edge length is,3x/23x/2 So, final Surface Area,A2=6(3x/2)2=6(9x2/4)=6x2(9/4)=9/4(A1)A2=6(3x/2)2=6(9x2/4)=6x2(9/4)=9/4(A1) So, Increase in Surface Area,dA=A2−A1=9/4(A1)−A1=A1(9/4−1)=A1(5/4)dA=A2−A1=9/4(A1)−A1=A1(9/4−1)=A1(5/4) So, the area increased by5/45/4 Now, percentage increase will be((5/4)∗100=1255/4)∗100=125% So, the percentage increase in the Surface Area of the cube will be 125%. |
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