1.

If each edge of a cuboid of surface area S is doubled, then surface area of the new cuboid isA. 2 SB. 4 SC. 6 SD. 8 S

Answer»

Correct option is B. 4 S

Given,

Let edges of cuboid = l , b , h

Surface area of cuboid = 2(lb + bh + hl)

New edges of cuboid = 2l , 2b , 2h

New surface area of cuboid = 2(4lb + 4bh + 4hl)

= 4 x 2(lb + bh + hl) = 4S



Discussion

No Comment Found