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If each edge of a cuboid of surface area S is doubled, then surface area of the new cuboid isA. 2 SB. 4 SC. 6 SD. 8 S |
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Answer» Correct option is B. 4 S Given, Let edges of cuboid = l , b , h Surface area of cuboid = 2(lb + bh + hl) New edges of cuboid = 2l , 2b , 2h New surface area of cuboid = 2(4lb + 4bh + 4hl) = 4 x 2(lb + bh + hl) = 4S |
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