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If ∫e2x(cot2x−1cosx⋅sinx)dx=Ae2xcosec (Bx)+C, then the value of A2+B2 is equal to |
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Answer» If ∫e2x(cot2x−1cosx⋅sinx)dx=Ae2xcosec (Bx)+C, then the value of A2+B2 is equal to |
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