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If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+c, where c is a constant of integration, then g(0) is equal to : |
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Answer» If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+c, where c is a constant of integration, then g(0) is equal to : |
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