1.

If ∫(e2x+2ex−e−x−1)e(ex+e−x)dx=g(x)e(ex+e−x)+c, where c is a constant of integration, then g(0) is equal to :

Answer»

If (e2x+2exex1)e(ex+ex)dx=g(x)e(ex+ex)+c, where c is a constant of integration, then g(0) is equal to :



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