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If `e^(-pi//2) lt theta lt pi //2 ` ,then =A. cos (log `theta) gt ` log (cos `theta`)B. cos (log `theta) lt` log (cos `theta`)C. cos (log `theta`) = log (cos `theta`)D. None of these |
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Answer» Correct Answer - A since `e^(-pi//2) lt theta lt pi//2` `implies "log" e^(-pi//2) lt "log" theta lt "log" pi//2` `implies -(pi)/(2) lt "log" theta lt "log" (pi)/(2) lt 1 lt pi//2` i.e., `-(pi)/(2) lt "log" theta lt (pi)/(2)` But 0`lt` cos `theta lt 1` so ,log (cos `theta) lt` log (1) `implies ` log (cos `theta) lt 0` Hence cos (log `theta) lt ` log (cos `theta`) |
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