1.

If `(dy)/(dx)=y+3 and y(0)=2`, then y(ln 2) is equal toA. 7B. 5C. 13D. `-2`

Answer» Correct Answer - A
We have,
`(dy)/(dx)=y+3`
`rArr" "(1)/(y+3)dy=dx`
`rArr" "int(1)/(y+3)dy=int 1.dx`
`rArr" "log(y+3)=x+C" …(1)"`
It is givne that y(0) = 2 i.e. y = 2 when x = 0.
`therefore" "log 5 =C" [Putting y = 2, x = 0 in (i)]"`
Substituting the value of C in (i), we get
`log(y+3)=x+log5`
Putting x = ln 2, we get
`y+3=5e^(log2)rArr y+3=10rArr y = 7`


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