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If ∫dx(x2−1)√x=p⋅ln∣∣∣f(x)−1f(x)+1∣∣∣+q⋅tan−1(g(x))+C.Then the value of f(4)p−q⋅g(1)=(Where p,q are fixed constants and C is integration constant) |
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Answer» If ∫dx(x2−1)√x=p⋅ln∣∣∣f(x)−1f(x)+1∣∣∣+q⋅tan−1(g(x))+C. Then the value of f(4)p−q⋅g(1)= (Where p,q are fixed constants and C is integration constant) |
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