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If `(dx)/(dt)=k[H_(3)O^(+)]n` and rate becomes 100 times when pH changes from 2 to 1 Hence order of reactions is |
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Answer» `(dx)/(dt)=k[H^+]^nimplies r_1=k[10^(-2)]^nimplies r_2=k[10^(-1)]^n` `r_1=k[10^(-2n)]`…(i) `100 r=k(10^(-n))`…(ii) Divide:(i)/(ii) `implies 1/100=10^(-n)implies n=2` |
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