1.

If DeltaU and DeltaW represent the increase in internal energy and work done by the system respectively in a thermodynamical process which of the following is true?

Answer»

`DeltaU=-DeltaW` , in an adiabatic process
`DeltaU=DeltaW`, in an ISOTHERMAL process
`DeltaU=DeltaW` in an adiabatic process
`DeltaU=-DeltaW` in an isothermal process

SOLUTION :According to first LAW of thermodynamics ,
`DeltaQ=DeltaU+DeltaW`
For an adiabatic process `DeltaQ=0`
`THEREFORE DeltaU=-DeltaW`
For an isothermal process,
`DeltaU=0`
`therefore DeltaQ=DeltaW`


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