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If DeltaU and DeltaW represent the increase in internal energy and work done by the system respectively in a thermodynamical process which of the following is true? |
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Answer» `DeltaU=-DeltaW` , in an adiabatic process `DeltaQ=DeltaU+DeltaW` For an adiabatic process `DeltaQ=0` `THEREFORE DeltaU=-DeltaW` For an isothermal process, `DeltaU=0` `therefore DeltaQ=DeltaW` |
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