1.

If DeltaH_(f(C_(2)H_(6)))^(0)(g) = -85 KJH mol^(-1) , DeltaH_(f(C_(3)H_(8)))^(0) (g) = -104 KJ mol^(-1), DeltaH^(0)for C (s) rarr C(g) is 718 KJ mol^(-1) and heat of formation of H-atom is 218 KJmol^(-1) then :

Answer»

`DeltaH_(C-C) = 345` KJ
`DeltaH_(C-H) = 414` KJ
`DeltaH_(H-H)=436 KJ`
`DeltaH_(H-H) = 436` KJ

Solution :`2C + 3H_(2) rarr C_(2)H_(6)`
Also, `DeltaH_(f(C_(2)H_(6)))^(0)(G) = 2xx 718 + 3xx436 - a - 6b"" (DeltaH_(C-C) = a, DeltaH_(C-H) = B)`
`a+ 6b = 2829"""…."(i)`
`3C + 4H_(2) rarrC_(2)H_(8)`
`DeltaH_(f(C_(3)H_(8)))^(0) (g) = 3XX 718 + 4 xx 436 - 2a - 8b`
`2a + 8b = 4002"""....."(ii)`
`a = 345"&" b=414 KJ.`


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