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IF DE PARALLEL BC, CD PARALLEL EF, THEN PROVE THAT, AD^2=AB*AF |
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Answer» Step-by-step EXPLANATION: this question can be SOLVED by using thales theorm corollary or BPT corollary in ADC,by BPT we get af/ad=ae/ac . eq1 in ABC,by BPT we get ad/ab=ae/ac . eq2 from 1 and 2 we get af/ad=ad/ab by cross multiplying ad²=af×ab |
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