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If ∫cot x⋅ln(sin x)dx=f(x)+C, then the number of solution(s) of the equation f(x)=0 in [0,2π], is(where C is constant of integration) |
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Answer» If ∫cot x⋅ln(sin x)dx=f(x)+C, then the number of solution(s) of the equation f(x)=0 in [0,2π], is (where C is constant of integration) |
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