1.

If ∫cot x⋅ln(sin x)dx=f(x)+C, then the number of solution(s) of the equation f(x)=0 in [0,2π], is(where C is constant of integration)

Answer» If cot xln(sin x)dx=f(x)+C, then the number of solution(s) of the equation f(x)=0 in [0,2π], is

(where C is constant of integration)


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