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If∫cot(2tan−1⎷√1+√x−x14√1+√x+x14)dx=q.xp4p+C, x > 0 (where p & q are relatively prime and C is constant of integration), then |
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Answer» If∫cot(2tan−1 ⎷√1+√x−x14√1+√x+x14)dx=q.xp4p+C, x > 0 (where p & q are relatively prime and C is constant of integration), then |
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