If cosx=1−t21+t2 and siny=2t1+t2 where t∈(−1,0), then the value – InterviewSolution

1.	If cosx=1−t21+t2 and siny=2t1+t2 where t∈(−1,0), then the value of 4d2ydx2−32dydx−12yx at (x,y)=(1,−1) is
Answer» If $cos x = \frac{1 - t^{2}}{1 + t^{2}}$ and $sin y = \frac{2 t}{1 + t^{2}}$ where $t \in (- 1, 0)$ , then the value of $4 \frac{d^{2} y}{d x^{2}} - \frac{3}{2} \frac{d y}{d x} - \frac{1}{2} \frac{y}{x}$ at $(x, y) = (1, - 1)$ is

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