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If (cosecθ−sinθ)=a3 and (secθ−cosθ)=b3 , prove that a2b2(a2+b2)=1 |
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Answer» If (cosecθ−sinθ)=a3 and (secθ−cosθ)=b3 , prove that a2b2(a2+b2)=1 |
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