If cosec A-sinA=p and secA-cosA=q, prove that p^2q^2(p^2+q^2+3)=1

1.	If cosec A-sinA=p and secA-cosA=q, prove that p^2q^2(p^2+q^2+3)=1
Answer» Step-by-step explanation: Answer Open in ANSWR app LHS : q(p2−1) =(secθ+cosec θ)[(sinθ+cosθ)2−1] =(cosθ1+sinθ1)(2sinθcosθ) =(sinθcosθsinθ+cosθ)(2sinθcosθ) =2(sinθ+cosθ)=2P = RHS

Answer»

Step-by-step explanation:

Answer

Open in ANSWR app

LHS :

q(p2−1)

=(secθ+cosec θ)[(sinθ+cosθ)2−1]

=(cosθ1+sinθ1)(2sinθcosθ)

=(sinθcosθsinθ+cosθ)(2sinθcosθ)

=2(sinθ+cosθ)=2P = RHS

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If cosec A-sinA=p and secA-cosA=q, prove that p^2q^2(p^2+q^2+3)=1​

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If cosec A-sinA=p and secA-cosA=q, prove that p^2q^2(p^2+q^2+3)=1