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If cos2A=1-tan^2A/1+tan^2A then a = |
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Answer» COS2A = cos^2 A - sin^2 A = cos^2 A ( 1 - tan^2 A) = (1 - tan^2 A)/sec^2 A = (1 - tan^2 A)/(1 + tan^2 A) Step-by-step EXPLANATION: cos2A = cos^2 A - sin^2 A = cos^2 A ( 1 - tan^2 A) = (1 - tan^2 A)/sec^2 A = (1 - tan^2 A)/(1 + tan^2 A) but this is not a .this is PROVES |
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