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If cos² alpha + cos² beta = 2 Find tan³ alpha + sin^5 beta |
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Answer» Answer: Shorya9017Maths AryaBhatta Step-by-step explanation: COS alpha / SIN alpha = 1/2. , so sin alpha/ cos alpha = 2 tan alpha = sin alpha / cos alpha. So tan alpha = 2 1/cos BETA = -5/3 cos beta = -3/5 sin beta = √ 1- cos ^2 beta sin beta = √1-(-3×-3/5×5) = √1-9/25 = √25-9/25 sin beta = √ 16/25 = 4/5 tan beta = sin beta / cos beta cos beta = -3/5 , sin beta = 4/5 tan beta =( 4/5 )/ (-3/5) tan beta =-4/3 tan (alpha+beta) = tan alpha + tan beta / 1-tan alpha× tan beta. ={ 2 + (-4/3)}/1-2×(-4/3) =(6 -4 /3 ) / 1+(8/3) = (2/3 ) / 3+8/3 =(2/3) / 11/3 =2/3 × 3/11 tan (alpha + beta ) = 2/11 Hope it may help you ♥ plzz mark as BRAINLIST... |
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