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If cos theta equal to 2 by 3 then find the value of 2 sec square theta + 2 10 squared theta minus 7 |
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Answer» Answer: Step-by-step EXPLANATION: I suppose the equation is 2(secθ)^2 + (tanθ)^2 - 7. cosθ=2/3 (Given) So to find the value of secθ we can use secθ = 1/(cosθ) secθ = 1/(2/3) = 3/2 We can also use the THEOREM (tanθ)^2 = (secθ)^2 - 1 So now the equation is 2(secθ)^2 + [(secθ)^2 - 1] - 7 By solving this we get 3(secθ)^2 - 8 By PUTTING the value of secθ we get [3*(4/9)] - 8 = (4/3) - 8 = -20/3 |
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