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If cos ɵ = 3÷5 then what is the value of 6tan ɵ - 5cos ɵ ? |
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Answer» Given : cosθ = 3/5 To find : the VALUE of (6tanθ - 5cosθ) SOLUTION : it is given that, cosθ = 3/5 = base/hypotenuse, so, base = 3 and hypotenuse = 5 from Pythagoras theorem, hypotenuse² = altitude² + base² ⇒5² = altitude² + 3² ⇒altitude = 4 now, tanθ = altitude/base = 4/3 now 6tanθ - 5cosθ = 6 × 4/3 - 5 × 3/5 = 8 - 3 = 5 Therefore the value of (6tanθ - 5cosθ) = 5. |
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