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If cos(A-B) = 3/5 and tanA*tanB = 2 then (a) cosA*cosB= 1/5 (c) cos(A+B)= -1/5 (b) sinA*sinB= 2/5 (d) sinA*sinB=4/5 |
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Answer» If cos(A-B) = 3/5 and tanA*tanB = 2 then (a) cosA*cosB= 1/5 (c) cos(A+B)= -1/5 (b) sinA*sinB= 2/5 (d) sinA*sinB=4/5 |
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