1.

If cos(A-B) = 3/5 and tanA*tanB = 2 then (a) cosA*cosB= 1/5 (c) cos(A+B)= -1/5 (b) sinA*sinB= 2/5 (d) sinA*sinB=4/5

Answer»

If cos(A-B) = 3/5 and tanA*tanB = 2 then

(a) cosA*cosB= 1/5 (c) cos(A+B)= -1/5

(b) sinA*sinB= 2/5 (d) sinA*sinB=4/5



Discussion

No Comment Found