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If cos−1x−cos−1y2=α where −1≤x≤1, −2≤y≤2, x≤y2, then for all x,y, 4x2−4xycosα+y2 is equal to : |
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Answer» If cos−1x−cos−1y2=α where −1≤x≤1, −2≤y≤2, x≤y2, then for all x,y, 4x2−4xycosα+y2 is equal to : |
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