Saved Bookmarks
| 1. |
If `cos^(-1)lambda+cos^(-1)mu+cos^(-1)gamma=3pi,`then find the value of `lambdamu+mugamma+gammalambda` |
|
Answer» `cos^(-1)lambda+cos^(-1)mu+cos^(-1)gamma=3pi` `0<=cos^(-1)x<=x` `cos^(-1)lambda=cos^(-1)mu=cos^(-1)gamma=pi` `cos^(-1)lambda=pi` `cospi=lambda=-1` `lambda=mu=gamma=-1` `lambdamu+mulambda+gammalambda=3` `1+1+1=3`. |
|