If `cos^(-1)(cos 4)gt3x^(2)-4x` thenA. `x in (-oo,(2-sqrt(6pi-8))/(3)`B. `x in ((2+sqrt(6pi-87))/(3),oo)`C. `x in ((2+sqrt(6pi-8))/(3),oo)`D. `x in ((2-sqrt(p6pi-8))/(3),(2+sqrt(6pi-8))/(3)`

If `cos^(-1)(cos 4)gt3x^(2)-4x` thenA. `x in (-oo,(2-sqrt(6pi-8))/(3)`

1.	If `cos^(-1)(cos 4)gt3x^(2)-4x` thenA. `x in (-oo,(2-sqrt(6pi-8))/(3)`B. `x in ((2+sqrt(6pi-87))/(3),oo)`C. `x in ((2+sqrt(6pi-8))/(3),oo)`D. `x in ((2-sqrt(p6pi-8))/(3),(2+sqrt(6pi-8))/(3)`
Answer» Correct Answer - `oo` We have `cos^(-1)(cos4)gt3x^(2)-4x` `rarr cos^(-1)(cos(2pi-4))gt3x6(2)-4x` `rarr 2pi -4 gt3x^(2)-4x^(2)` `rarr 3x^(2)-4x-(2pi-4)lt0` `rarr (2-sqrt(6pi-8))/(3)ltxlt(2+sqrt(6pi-8))/(3)`

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