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If co sec 0- k then prove that cos 0 = k2-1/k2+1 |
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Answer» Given, cosecθ+cotθ=K sinθ 1 + sinθ cosθ =k sinθ 1+cosθ =k 1+cosθ=ksinθ Squaring both side, (1+cosθ) 2 =k 2 sin 2 θ (1+cosθ) 2 =k 2 (1−cos 2 θ) (1+cosθ).(1+cosθ)=k 2 (1+cosθ)(1−cosθ) 1+cosθ=k 2 (1−cosθ) 1+cosθ=k 2 −k 2 cosθ 1+(1+k 2 )cosθ=k 2
(1+k 2 )cosθ=k 2 −1 cosθ= k 2 +1 k 2 −1 NEED NEW FOLLOWERS! PLZZZZZZ FOLLOW ME BRO/SISO!❤❤❤❤ Tried my best!! HOPE IT HELPS!! PPLLLLLLZZZZZZZZ MARK MY ANSWERS AS BRAINLIEST [gain 3 points],THANK MY ANSWERS!! ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ |
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