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If CD = 5 then find ∠ACD,∠BCD . Find AB, AD, BD, BC. Find the angles of triangle ABC. If the angles are 45°, 60°, 75° find the ratio of the sides? |
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Answer» ∠ACD = 45° (∵ A = 45° ∠ADC = 90°) ∠BCD = 30°(180 - (90 + 60)), If CD = 5 \(BD=\frac{5}{\sqrt{3}},AD=5\) AB = BD + AD = \(\frac{5}{\sqrt{3}}+5=7.886\) AB = 7.886 BC = \(\frac{5}{\sqrt{3}}\times2=\frac{10}{\sqrt{3}}=5.77,\) AC = \(5\sqrt{2}\) In ∆ABC ∠A = 45°, ∠B = 60°, ∠C = 75° Ratio of sides = 5.77 : 7.09 : 7.88 |
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