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If both 112 and 33 are factors of the number a 43 62 1311, what is the smallest possible value of a'? |
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Answer» Answer: Step-by-step explanation: 112 = 16 * 7 33 = 11 * 3 a * 43 * 62 * 1311 = (2 ^4 * 7) * k1 a * 43 * 31 * 2 * 1311 = (2^4 *7) * k1 a * 43 * 31 * 2 * 3 *437 = (2^4 *7) * k1 therefore MINIMUM VALUE of a shud be 2^3 * 7 = 56 for the second factor, a * 43 * 62 * 1311 = (11 * 3) * k2 a * 43 * 31 * 2 * 3 *437 = (11 * 3) * k2 so min = 11 |
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