If bcosx = a then prove cosecx + cotx = √ b + a / b - a

1.	If bcosx = a then prove cosecx + cotx = √ b + a / b - a
Answer» Given bcosx=aCosx=a/b. Equation (1)From identity Sinx=√1-cos²xSinx=√1-(a/b)²Sinx=√b²-a²/b. Equation (2)Now Cosecx+cotx=1/sinx. + Cosx/sinx =(1+cosx)/sinxFrom equation (1)&(2)=(1+a/b)÷(√b²-a²)/b=(b+a)÷(√b²-a²)=√(b+a)²÷(√b²-a²)=√(b+a)²/(b²-a²)=√(b+a)(b+a)/(b+a)(b-a)=√(b+a)/(b-a)Hence proved

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