1.

If (b-c)²,(c-a)², (a-b)² are in AP show that 1/(b-c), 1/(c-a), 1/(a-b) are in AP.

Answer» If (b-c)²,(c-a)², (a-b)² are in AP show that 1/(b-c), 1/(c-a), 1/(a-b) are in AP.


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