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If |ĀXB = 13A.B then the value of |Ā +B | is 11/2(1) (A? +B2 + AB)1/2 (2)(3) A+B(4) (A2+B2 13 + AB)12 |
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Answer» 4Explanation:[A][B]sintheta=A.B 13A.B=ABsin thetaA+B=A²+B²+ 2ABCos THETA = |
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