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If Arccos x >Arcsinx ,thena.0 less than equal to x ,less than 1/√2b. -1 less than equal to x ,less than 1/√2c.0 less than x ,less than 1/√2Here ,which option is right, a or b or c??Answer it with reason or explanation.I will surely mark it as brainliest.

Answer» ACCORDING to me, it's answer should be
a \: \: 0 \leqslant x < 1 \div \sqrt{2}
the reason is as below
assume
arc = l
so if
l \cos(x) > l \sin(x)
cancelling L from both SIDES we get
\cos(x) > \sin(x)
and for that condition to be TRUE your x has to be in
0 \leqslant x < 45 \: or \: \binom{\pi}{4}
but as that is not in options
REAL ANSWER ACCORDING TO ME SHOULD BE NONE OF THIS
but as it is not in options so I TRIED to check their cosine values
and that is matching with first option thus I am telling that your answer could be A


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