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If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits a photon of wavelength lambda. When it jumps from the 4^(th) orbit to the 3^(rd) orbit, the corresponding wavelength of the photon will be |
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Answer» `(20)/(7) lambda` `(1)/(lambda)=R((1)/(2^(2))-(1)/(3^(2)))...(1)` Wavelength of photon when electron makes transition from FORTH orbit to third orbit `(1)/(lambda.)=R((1)/(3^(2))-(1)/(4^(2)))...(2)` by taking ratio of (1) and (2) `(lambda.)/(lambda)=((1)/(4)-(1)/(9))/((1)/(9)-(1)/(16))=((5)/(36))/((7)/(144))=(20)/(7)` `:. lambda.=(20)/(7) lambda` |
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