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If An=1+q+q2+q3+⋯+qn and Bn=1+(q+12)+(q+12)2+⋯+(q+12)n,q≠1, then n+1C1+ n+1C2⋅A1+ n+1C3⋅A2+⋯+ n+1Cn+1⋅An=

Answer»

If An=1+q+q2+q3++qn and Bn=1+(q+12)+(q+12)2++(q+12)n,q1, then

n+1C1+ n+1C2A1+ n+1C3A2++ n+1Cn+1An=



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