If alpha, beta are the zeros of the polynomial f(x) = x2 – 3x + 2, t

1.	If alpha, beta are the zeros of the polynomial f(x) = x2 – 3x + 2, then find 1/ alpha + 1/beta. tumhare question me sabpe 2 answer hai
Answer» Step-by-step EXPLANATION: $Answer:\begin{gathered}\tt{\alpha + \beta = \frac{-b}{c} = 3}\\\end{gathered}α+β=c−b=3 \ \\begin{gathered}\tt{\alpha \beta = \frac{c}{a} = 2}\\\end{gathered}αβ=ac=2 \\begin{gathered}\tt{\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}}\\\end{gathered}α1+β1=αβα+β= \> \begin{gathered}\tt{\frac{3}{2}}\\\end{gathered}23______________$

If alpha, beta are the zeros of the polynomial f(x) = x2 – 3x + 2, then find 1/ alpha + 1/beta. tumhare question me sabpe 2 answer hai

Answer»

Step-by-step EXPLANATION:

$Answer:\begin{gathered}\tt{\alpha + \beta = \frac{-b}{c} = 3}\\\end{gathered}α+β=c−b=3 \ \\begin{gathered}\tt{\alpha \beta = \frac{c}{a} = 2}\\\end{gathered}αβ=ac=2 \\begin{gathered}\tt{\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}}\\\end{gathered}α1+β1=αβα+β= \> \begin{gathered}\tt{\frac{3}{2}}\\\end{gathered}23______________$

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If alpha, beta are the zeros of the polynomial f(x) = x2 – 3x + 2, then find 1/ alpha + 1/beta. tumhare question me sabpe 2 answer hai ​

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If alpha, beta are the zeros of the polynomial f(x) = x2 – 3x + 2, then find 1/ alpha + 1/beta. tumhare question me sabpe 2 answer hai