If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a qua

1.	If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a quadratic polynomial whose zeroes are half the zeroes of given polynomial.
Answer» ANSWER: $\alpha + \beta = 7 \\ \alpha \beta = 10 \\ \\ {x}^{2} - ( \frac{ \alpha }{2} + \frac{ \beta }{2} )x + \frac{ \alpha }{2} \times \frac{ \beta }{2} = 0 \\ {x}^{2} - \frac{1}{2} ( \alpha + \beta )x + \frac{ \alpha \beta }{4} = 0 \\ \\ {x}^{2} - \frac{7}{2} x - \frac{10}{4} = 0$

If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a quadratic polynomial whose zeroes are half the zeroes of given polynomial.

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$\alpha + \beta = 7 \\ \alpha \beta = 10 \\ \\ {x}^{2} - ( \frac{ \alpha }{2} + \frac{ \beta }{2} )x + \frac{ \alpha }{2} \times \frac{ \beta }{2} = 0 \\ {x}^{2} - \frac{1}{2} ( \alpha + \beta )x + \frac{ \alpha \beta }{4} = 0 \\ \\ {x}^{2} - \frac{7}{2} x - \frac{10}{4} = 0$

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If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a quadratic polynomial whose zeroes are half the zeroes of given polynomial.​

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If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a quadratic polynomial whose zeroes are half the zeroes of given polynomial.