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If alpha, beta are roots of ax2 + bx + c = 0, then the equation ax2 - bx (x - 1) + c(x - 1)2 = 0 has roots1) alpha/(1-alpha), beta/(1-beta)2) (1- alpha)/alpha, (1-beta)/beta3) alpha/(1+alpha), beta/(1+beta)4) (1+alpha)/alpha, (1+beta)/beta |
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Answer» If alpha, beta are roots of ax2 + bx + c = 0, then the equation ax2 - bx (x - 1) + c(x - 1)2 = 0 has roots 1) alpha/(1-alpha), beta/(1-beta) 2) (1- alpha)/alpha, (1-beta)/beta 3) alpha/(1+alpha), beta/(1+beta) 4) (1+alpha)/alpha, (1+beta)/beta |
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