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If alpha and bita are the roots of the quadratic equation ax²+bx+c=0 then 1/alpha+b + 1/abita+b= |
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Answer» Step-by-step explanation: if ALPHA is root a(alpha)²+b(alpha) = -C a(beta)²+b(beta)= -c [1/a(alpha)+b]×(alpha)/(alpha)=(alpha)/-c same for beta then (beta)/-c 1/a(alpha)+b +1/a(beta)+b =b/AC Mark as brainiest ANSWER |
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