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If alpha and beta zeroes of polynomial x^2-6x+7 find alpha^2/beta+beta^2/alpha |
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Answer» from x^2-6x+7 α+β=6 αβ=7 α^2 / β + β^2 / αβ α^2+β^2 / αβ α^2+β^2+2αβ-2αβ / αβ (α+β)^2 - 2αβ / αβ (6)^2 - 2(7) / 7 36 - 14 / 7 22 / 7 |
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