1.

If alpha and beta zeroes of polynomial x^2-6x+7 find alpha^2/beta+beta^2/alpha

Answer»
from x^2-6x+7
α+β=6
αβ=7

α^2 / β + β^2 / αβ

α^2+β^2 / αβ

α^2+β^2+2αβ-2αβ / αβ

(α+β)^2 - 2αβ / αβ

(6)^2 - 2(7) / 7

36 - 14 / 7

22 / 7





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