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If alpha and beta are zeroes of polynomial ax^2+bx+c.Find1. alpha^3+beta^32. alpha-beta |
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Answer» α and β are the ZEROES of the polynomial ax² + bx + c. ★ Sum of the zeroes : α + β = -b/a ★ Product of the zeroes : αβ = c/a Case 1 : α³ + β³ [ Given ]
α³ + β³ ⇒ ( α + β ) ( α² + β² - αβ ) α³ + β³ ⇒ ( α + β ) [(α² + β² +2αβ ) - 3αβ ] α³ + β³ ⇒ ( α + β ) [ ( α + β )² - 3αβ ] α³ + β³ ⇒ -b/a [ ( -b/a )² - 3c/a ] α³ + β³ ⇒ -b/a [ b²/a² - 3c/a ] α³ + β³ ⇒ -b/a ( b² -3ac / a² ) α³ + β³ ⇒ -b³ + 3ac / a³ Case 2 : α - β [ Given ] Squaring ,we get ( α - β )² ⇒ ( α + β )² - 4αβ ( α - β )² ⇒ ( α + β )² - 4αβ ★ Putting the values ( α - β )² ⇒ ( -b/a )² - 4 × c/a ( α - β )² ⇒ b²/a² - 4c/a ( α - β )² ⇒ b² - 4ac / a² α - β ⇒ √b² - 4ac / a |
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