1.

If alpha and beta are the zeros of the polynomial ax2+bx+c find the value of (alpha+1) (beta+1)Solve it the clearest for brainliest

Answer»

Given

A POLYNOMIAL ax²+bx+c

To Find

(\alpha+<klux>1</klux>)(1+\beta)

Solution

If the zeroes are (\alpha)&(\beta)

We know that

\alpha+\beta=\frac{-b}{a}

&

\alpha\times\beta=\frac{c}{a}

PUTTING VALUES in it

(\alpha+1)(1+\beta)

Solving it

\imples(\alpha\times\beta+\alpha+\beta+1)

=>\frac{-b}{a}+\frac{c}{a}+1

=>\frac{-b+c+a}{a}



Discussion

No Comment Found

Related InterviewSolutions