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If alpha and beta are the zeros of quadratic polynomial 4x2-5x-1 find the value of alpha/beta+beta/alpha |
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Answer» 4x^2 - 5x - 1 a = 4 B = -5 c = -1 α + β = -b / a = 5 / 4 α * β = -1 / 4 α / β + β / α = (α^2 + β^2)/αβ = ( α + β)^2 - 2αβ
= (5/4)^ 2 - 2*(-1/4)
= 25/16 + 1/2 = 66 / 32 = 33 / 16
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