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If `alpha and beta` are the zeros of a quadratic polynomial such that `alpha+beta= 24 and alpha-beta = 8,` find a quadratic polynomial having `alpha and beta` as its zeros. |
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Answer» `alpha +beta=24`....(1) and `alpha-beta=8`......(2) and (1) and (2) we get`2alpha=32` thus `alpha=16` and `beta=8`. now a quadratic equation is of the form `x^2-sx+p=0` where s and p are sum and product of the roots here s=24 and p=128 substituting values eqn s=>`x^2-24x+128=0` |
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