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If `alpha and beta` are the zeros of a quadratic polynomial such that `alpha+beta= 24 and alpha-beta = 8,` find a quadratic polynomial having `alpha and beta` as its zeros.

Answer» `alpha +beta=24`....(1) and `alpha-beta=8`......(2)
and (1) and (2) we get`2alpha=32` thus `alpha=16` and `beta=8`.
now a quadratic equation is of the form `x^2-sx+p=0` where s and p are sum and product of the roots
here s=24 and p=128
substituting values eqn s=>`x^2-24x+128=0`


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