If alpha and Beeta are zeroes of the polynomial ax^2+61x+6a. Find the

1.	If alpha and Beeta are zeroes of the polynomial ax^2+61x+6a. Find the value of Beeta and alpha?
Answer» ANSWER: $\alpha = \frac{-61 + \sqrt{3697} }{2}\\$ $\beta = \frac{-61 - \sqrt{3697}}{2}$ Step-by-step explanation: BRO I HOPE that you know the quadratic formula if not when you STUDY it then try to understand this QUESTION. Hope it helps : )

If alpha and Beeta are zeroes of the polynomial ax^2+61x+6a. Find the value of Beeta and alpha?

Answer»

ANSWER:

$\alpha = \frac{-61 + \sqrt{3697} }{2}\\$

$\beta = \frac{-61 - \sqrt{3697}}{2}$

Step-by-step explanation:

BRO I HOPE that you know the quadratic formula if not when you STUDY it then try to understand this QUESTION.

Hope it helps : )

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If alpha and Beeta are zeroes of the polynomial ax^2+61x+6a. Find the value of Beeta and alpha?​

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If alpha and Beeta are zeroes of the polynomial ax^2+61x+6a. Find the value of Beeta and alpha?