1.

if alpha and beeta are the zeroes of the quadratic polynomial f[x]=6x^2 +x-2. Find the value of alpha/beeta + beeta/alpha

Answer»

Answer:

ALPHA =1/2 & beta = -2/3

Step-by-step explanation:

in middle TERM factorisation:

break X = 4x - 3x

then FACTORS will be:

(3x+2)(2x-1)=0

then,x=-2/3 or x=1/2



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