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if alpha and beeta are the zeroes of the quadratic polynomial f[x]=6x^2 +x-2. Find the value of alpha/beeta + beeta/alpha |
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Answer» Answer: ALPHA =1/2 & beta = -2/3 Step-by-step explanation: in middle TERM factorisation: break X = 4x - 3x then FACTORS will be: (3x+2)(2x-1)=0 then,x=-2/3 or x=1/2 |
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