If alfa and beta are the zeroes of polynomial ax2+bx+c then find the v

1.	If alfa and beta are the zeroes of polynomial ax2+bx+c then find the value of alfa plus beta
Answer» bx + c Given quadratic polynomial is f(x)=ax^ 2 + The zeroes of the polynomial are aß zeros = - b/a Sum of the alpha + beta = - b/a Poduct of the alpha beta=> c a Squaring both sides, zeros = c/a Now, alpha + beta = - b/a =>( alpha+ beta)^ 2 =-( b a )^ 2 => alpha^ 2 + beta^ 2 +2 alpha beta= b^ 2 a^ 2 =>a^ 2 + beta^ 2 +2( c a )= b^ 2 a^ 2 => alpha^ 2 + beta^ 2 = b^ 2 a^ 2 - 2c a => alpha^ 2 + beta^ 2 = b^ 2 -2ca a^ 2 =>a^ 2 + beta^ 2 = b^ 2 -2ac a^ 2 $^{<span class="vlist" styl}$

If alfa and beta are the zeroes of polynomial ax2+bx+c then find the value of alfa plus beta

Answer»

bx + c

Given quadratic polynomial is f(x)=ax^ 2 +

The zeroes of the polynomial are aß zeros = - b/a

Sum of the alpha + beta = - b/a Poduct of the alpha beta=> c a Squaring both sides, zeros = c/a

Now, alpha + beta = - b/a

=>( alpha+ beta)^ 2 =-( b a )^ 2

=> alpha^ 2 + beta^ 2 +2 alpha beta= b^ 2 a^ 2

=>a^ 2 + beta^ 2 +2( c a )= b^ 2 a^ 2

=> alpha^ 2 + beta^ 2 = b^ 2 a^ 2 - 2c a

=> alpha^ 2 + beta^ 2 = b^ 2 -2ca a^ 2

=>a^ 2 + beta^ 2 = b^ 2 -2ac a^ 2

$^{<span class="vlist" styl}$

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If alfa and beta are the zeroes of polynomial ax2+bx+c then find the value of alfa plus beta

bx + c

Given quadratic polynomial is f(x)=ax^ 2 +

The zeroes of the polynomial are aß zeros = - b/a

Sum of the alpha + beta = - b/a Poduct of the alpha beta=> c a Squaring both sides, zeros = c/a

Now, alpha + beta = - b/a

=>( alpha+ beta)^ 2 =-( b a )^ 2

=> alpha^ 2 + beta^ 2 +2 alpha beta= b^ 2 a^ 2

=>a^ 2 + beta^ 2 +2( c a )= b^ 2 a^ 2

=> alpha^ 2 + beta^ 2 = b^ 2 a^ 2 - 2c a

=> alpha^ 2 + beta^ 2 = b^ 2 -2ca a^ 2

=>a^ 2 + beta^ 2 = b^ 2 -2ac a^ 2

<span class="vlist" styl

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