If AD be a median of an isosceles ABC and ∠A = 120° and AB = AC the – InterviewSolution

1.

If AD be a median of an isosceles ABC and ∠A = 120° and AB = AC then find ∠ADB.

Answer»

In ∆ABC

AB = AC (given)

∠B = ∠C = x (say)

x + x + 120° = 180°

=> 2x + 120 = 180°

=> 2x = 60°

=> x = 30°

∠ADB = 180° – (60° + 30°)

=> ∠ADB = 90°

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