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If acos3α+3acosαsin2α=m and asin3α+3acos2αsinα=n, then (m+n)23+(m−n)23= |
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Answer» If acos3α+3acosαsin2α=m and asin3α+3acos2αsinα=n, then (m+n)23+(m−n)23= |
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