1.

If accidently the calorimeter remained open to atmosphere for some time during the experiment, due to which the steady state temperature comes out to be 30^(@)C, then total heat loss to surrounding during the experiment, is (Use the specific heat capacity of the liquid from previous questions).

Answer»

`20 kcal`
`15 kcal`
`10 kcal`
`8 kcal`

SOLUTION :Heat given by the SPHERE
`=(1000)(1//2)(80-30) = 25000 cal`
Heat absorbed by the water calomiter SYSTEM
`=(900)(1)(30-20)+(200)(1//2)(30-20)`
`=10,000 cal`
So heat loss to surrounding =`15000 cal`.


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