If ABCD is rectangle AB =x-3y ,AD=10cm CD=12cm BC =2x+y find x and y�

1.	If ABCD is rectangle AB =x-3y ,AD=10cm CD=12cm BC =2x+y find x and y
Answer» Step-by-step EXPLANATION: Since, ABCD is a Rectangle & Opposite sides of a Rectangle are Equal Thus, x-3y=12... (1) and 2x+y=10..... (2) Solving 1 & 2 using Elimination, we GET x-3y=12 6x+3y=30 ____________ 7x=42 Thus, *x=6* *& y=* -2 *Answer*

If ABCD is rectangle AB =x-3y ,AD=10cm CD=12cm BC =2x+y find x and y

Answer»

Step-by-step EXPLANATION:

Since, ABCD is a Rectangle & Opposite sides of a Rectangle are Equal

Thus, x-3y=12... (1)

and 2x+y=10..... (2)

Solving 1 & 2 using Elimination, we GET

x-3y=12

6x+3y=30

____________

7x=42

Thus, x=6 & y= -2 Answer

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If ABCD is rectangle AB =x-3y ,AD=10cm CD=12cm BC =2x+y find x and y​

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If ABCD is rectangle AB =x-3y ,AD=10cm CD=12cm BC =2x+y find x and y