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If ABCD is a square then show that the points A, B, C and D are concyclic. |
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Answer» Answer with explanation: It is given that , ABCD is a SQUARE. Measure of each of interior Angles of Square is 90°. That is, ∠A=∠B=∠C=∠D=90° Now , sum of OPPOSITE angles ∠A + ∠C = 90° + 90° =180° Also, ∠B + ∠D == 90° + 90° =180° If you plot a Quadrilateral, passing through POINTS , A , B, C and D , Then, ∠A + ∠C=180° as WELL as , ∠B + ∠D=180° Showing that points , A, B, C and D are Con-cyclic. |
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